Simple İntegral question Check

[Arman777]

Homework Statement

$\int \frac{x}{\left(C-x\right)^2}dx=?$
Here $C$ is a constant

Homework Equations

The Attempt at a Solution

$c-x=u$ then $dx=-du$
then it becomes,
$\int \frac{u-c}{\left(u\right)^2}du$
$\int \frac{u}{u^2}-\frac{c}{u^2}du$
From there I found
$ln\left(c-x\right)+\frac{c}{c-x}$
but symbolab says its,
$ln\left(c-x\right)+\frac{x}{c-x}$
I cannot see how ??

 

[fresh_42]

Probably a typo somewhere.
http://www.wolframalpha.com/input/?i=int(x/(c-x)^2)dx

 

[Arman777]

Probably a typo somewhere.
http://www.wolframalpha.com/input/?i=int(x/(c-x)^2)dx

I hate symobolab

 

[alan2]

It's probably quicker to just differentiate your result than to check it with software from which you learn nothing.

 

[Arman777]

It's probably quicker to just differentiate your result than to check it with software from which you learn nothing.

Make sense never thought.