Simple KVL, KCL and Ohm's Law problems

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SUMMARY

The discussion focuses on solving a circuit problem using Kirchhoff's Voltage Law (KVL) and Kirchhoff's Current Law (KCL) to determine the value of the unknown resistor, Ro, in a circuit with a 192 V voltage drop. The equations derived include I_o + I_1 = 16A and -192V - (20 Ω)(I_o) + (20 Ω)(I_1) = 0. By substituting I_o into the equation 192 = I_o R_o, the value of Ro can be calculated. This approach effectively utilizes fundamental electrical engineering principles to solve for unknowns in circuit analysis.

PREREQUISITES
  • Understanding of Kirchhoff's Voltage Law (KVL)
  • Understanding of Kirchhoff's Current Law (KCL)
  • Basic knowledge of Ohm's Law
  • Familiarity with circuit analysis techniques
NEXT STEPS
  • Practice solving circuit problems using KVL and KCL
  • Learn advanced circuit analysis techniques such as mesh and nodal analysis
  • Explore the impact of different resistor values on circuit behavior
  • Study the application of Thevenin's and Norton's theorems in circuit simplification
USEFUL FOR

Electrical engineering students, circuit designers, and anyone interested in mastering circuit analysis techniques.

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simple04_fg.png


Given: In the circuit shown above, 192 V is dropped across the unknown resistor, Ro.

Required: Determine the value of Ro.

V = iR, KCL and KVL
I really don't know where to go on this one. I know that the right side's voltage will need to add up to zero, but that's about all I know.
 
Last edited:
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Call the current through the resistor R_o, I_o and call the current through the sole 20 \Omega resistor I_1 then we know that:

I_o + I_1 = 16A and starting from R_o and going clockwise we have -192V - (20 \Omega) (I_o) + (20 \Omega)(I_1)=0

Subsequently, 192 = I_o R_o.

3 equations and 3 unknowns.
 

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