Use KCL and KVL to find the power supplied by the two ideal sources

In summary, the problem involves finding the voltage across an ideal current source with values of 2A and 5A using Kirchoff's Voltage Law and Kirchoff's Current Law. The attempt at a solution involved using KVL and KCL for all closed paths and nodes, but the 5Ω and 3Ω resistors in parallel with voltage sources were not taken into account. It is necessary to eliminate these resistors before proceeding with the solution. A visual representation of the circuit with labeled mesh currents would also be helpful in solving the problem.
  • #1
MHGANAINY
1
0

Homework Statement


The Question wants to find the Voltage Across The Current Source 2A and 5A

Homework Equations


KVL
KCL
Ohm's Law

The Attempt at a Solution


I tried to Using KVL and KCL for all Closed paths and node but I just Couldn't Figure how to relate them to find the voltage across the ideal Current Source
 

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  • #2
Hi MHGANAINY, Welcome to Physics Forums!

You'll have to show your work so we can see what's missing or what went wrong.
 
  • #3
The first thing you should have done is to eliminate the 5Ω resistor in parallel with the 4Io source, and also eliminate the 3Ω resistor in parallel with the 5Vy source. Those two resistors have no effect on the rest of the circuit because they're in parallel with voltage sources.

Did this problem come from a textbook, or a handout given to you by the instructor? :)) It hurts my brain to look at it. Your instructor may be a sadist, in which case we are masochists. :rolleyes:

Show your circuit with the mesh currents labeled, for example as I1, I2, I3, etc. What did you get for the mesh currents?
 

1. How do I apply KCL and KVL to find the power supplied by two ideal sources?

KCL (Kirchhoff's Current Law) states that the algebraic sum of currents entering and exiting a node in a circuit must be equal to zero. KVL (Kirchhoff's Voltage Law) states that the algebraic sum of voltage drops and rises in a closed loop must be equal to zero. To apply these laws to find the power supplied by two ideal sources, we need to first draw a circuit diagram and label the currents and voltages. Then, we can use KCL to find the current flowing through each component and KVL to find the voltage across each component. Finally, we can use the formula P = VI to calculate the power supplied by each source.

2. What is an ideal source in a circuit?

An ideal source is a theoretical concept used in circuit analysis that represents a component that can supply a constant voltage or current with no internal resistance. This means that the voltage or current supplied by an ideal source will remain constant regardless of the loading conditions in the circuit.

3. Can KCL and KVL be used to find the power supplied by non-ideal sources?

Yes, KCL and KVL can be used to find the power supplied by non-ideal sources as long as the circuit is linear and the components obey Ohm's Law. However, the calculations may be more complex and may require additional equations or techniques.

4. What if there are multiple sources or loops in the circuit?

If there are multiple sources or loops in the circuit, we can still use KCL and KVL to find the power supplied by the two ideal sources. We just need to make sure that the equations we set up take into account all the sources and loops in the circuit. This may involve using superposition, where we analyze the circuit with one source at a time and then combine the results.

5. Are there any limitations to using KCL and KVL to find the power supplied by ideal sources?

KCL and KVL are based on certain assumptions and simplifications, so they may not be accurate in all cases. For example, they assume that the components in the circuit are linear and that there is no significant electromagnetic interference. Additionally, these laws may not take into account the effects of non-ideal components such as resistance in wires and connections. Therefore, it is important to carefully consider the limitations before applying KCL and KVL to find the power supplied by ideal sources.

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