Op-Amp Resistive Circuit Homework: Finding Vo in a Given Circuit

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SUMMARY

The discussion focuses on solving for the output voltage (Vo) across a 6k resistor in an op-amp resistive circuit. The key equation used is v_out/v_in = (R_1 + R_2)/R_1, leading to the conclusion that V_out = 4V_in. The participant struggles with determining V_in due to multiple unknown currents and equations derived from Kirchhoff's Voltage Law (KVL) and Kirchhoff's Current Law (KCL). A solution is suggested using the conservation of current to relate V+ and Vout, simplifying the problem to a resistive voltage divider.

PREREQUISITES
  • Understanding of op-amp circuit analysis
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Knowledge of Kirchhoff's Current Law (KCL)
  • Basic concepts of resistive voltage dividers
NEXT STEPS
  • Study op-amp feedback mechanisms and their impact on circuit behavior
  • Learn about resistive voltage divider calculations
  • Explore conservation of current principles in circuit analysis
  • Review examples of complex op-amp circuits to enhance problem-solving skills
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing or designing op-amp circuits will benefit from this discussion.

sojo
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Homework Statement


The attached picture is the circuit I have been given and I am asked to find Vo (the voltage drop across the 6k resistor.
Screen Shot 2018-10-28 at 9.01.31 PM.png


Homework Equations


v_out/v_in = (R_1 + R_2)/R_1
V+ = V-

The Attempt at a Solution


So I know that the voltage drop across the 6k resistor is just the output voltage of the op-amp since there is a ground there.
I used the v_out/v_in = 3+9/3 = 4, so I know V_out = 4V_in
The thing I am having issues with is finding the V_in. I feel like I have 7 unknown currents and I've written out a ton of equations using the KVL and KCL but I feel like I just keep running around in circles with all the unknowns.
Am I going to have to use all the KVL KCL equations to solve this, or is there some simpler method I am missing to find the Vin so I can find the Vout?
 

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sojo said:
v_out/v_in = (R_1 + R_2)/R_1
V+ = V-

You used "conservation of current" to establish V– in terms of Vout. So now you use that same "conservation of current" law to find V+ in terms of Vout and the 4V. The current into the resistor network equals the current that flows from the resistor network.
 
Just a hint: All you need is the positive feedback factor k+ (setting the 4V dc source equal to zero).
In this case, we have Rp=4k||5k=2.222k and the problem reduces to two simple resistive voltage divider in series.
This shouldn`t be a big problem.
 

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