- #1

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ω

^{2}=g/L

Where ω is the rotational velocity (or speed...I don't know which is the correct way to say this), g is the gravitational force and L is the length of the pendulum.

Thanks.

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- Thread starter llauren84
- Start date

- #1

- 44

- 0

ω

Where ω is the rotational velocity (or speed...I don't know which is the correct way to say this), g is the gravitational force and L is the length of the pendulum.

Thanks.

- #2

Doc Al

Mentor

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It's best to think of ω as the angular frequency of the motion. For a derivation, see this: http://hyperphysics.phy-astr.gsu.edu/HBASE/pend.html#c3"

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- #3

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Also g is the acceleration of free fall, not gravitational force.

- #4

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Thanks! I forgot.Also g is the acceleration of free fall, not gravitational force.

It's best to think of ω as the angular frequency of the motion. For a derivation, see this: http://hyperphysics.phy-astr.gsu.edu/HBASE/pend.html#c3"

Thanks! That helped.

I realise I should have put this in the homework help section...

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