Simple problem: logarithmic decrement

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SUMMARY

The discussion revolves around calculating the logarithmic decrement for a lightly damped harmonic oscillator with a frequency of 10 kHz, where the amplitude decays by 25% over 300 oscillations. The logarithmic decrement was calculated to be 9.59 x 10-4. The correct expression for amplitude as a function of time is A(t) = A0e-9.59t, as opposed to the incorrect formula A(t) = e-9.59t found in course notes, which fails to account for the initial amplitude A0.

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Homework Statement



Note this is exam revision rather than actual course work worth marks, so there is no need to be deliberately vague :)

The question comes in two parts, regarding a lightly damped harmonic oscillator with frequency 10 kHz and an amplitude that decays by 25% over 300 oscillations. First I am asked to calculate the logarithmic decrement, and then to make an expression that allows the amplitude to be calculated as a function of time elapsed.

Homework Equations



δ=(1/N)ln(A0/AN)

The Attempt at a Solution



The log decrement is 9.59x10-4. Easy. For the second part, simply rearranging the log decrement formula gives AN=A0e-Nδ. Knowing that N = 10,000*t, I get A(t)=A0e-9.59t.

What I do not understand is why my course notes give A(t)=e-9.59t. Why is this answer not multiplied by A0? Mathematically and physically, this does not make sense to me - the amplitude as a function of time definitely does depend on the initial amplitude! Am I right in thinking that is a mistake?

Thanks!
 
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Yes, you're right. If nothing else, the units don't match, that tells you the formula in your notes can't be correct.
 
Ah good, thanks for confirming that!
 

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