Simple projectile motion, yet stuck.

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SUMMARY

The discussion centers on a physics problem involving projectile motion where a ball is thrown horizontally from a height of 8.0 meters and lands 10.0 meters away. The calculated initial velocity of the ball is 7.16 m/s. The student utilized the equation for vertical displacement, dv = 1/2at², to determine the time of flight, which was found to be 1.63 seconds. Clarification was sought regarding the height at which the ball was caught, indicating potential confusion about the problem's parameters.

PREREQUISITES
  • Understanding of basic kinematics principles
  • Familiarity with projectile motion equations
  • Knowledge of gravitational acceleration (9.8 m/s²)
  • Ability to solve quadratic equations
NEXT STEPS
  • Study the derivation of projectile motion equations
  • Learn about horizontal and vertical components of motion
  • Explore the concept of range in projectile motion
  • Practice solving similar problems involving different heights and distances
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding projectile motion dynamics.

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Homework Statement


A student threw a ball horizontally out a window 8.0m above the ground. It was caught by another student 10.0m away. What was the initial velocity of the ball?
ANSWER PROVIDED: 7.16m/s

Homework Equations


dv=1/2at^2
t=vv/a
dh=vht

The Attempt at a Solution


dv=1/2at^2
8=1/2(9.8)t^2
√ans
t=1.63sec

The fact that I'm trying to find it's initial velocity causes my brain to become a blank slate when deciding on what my next step should be (if the first is even right).
 
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is the other student supposed to be at ground level or something? What's the height which the ball is caught?
 

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