Simple Projectile Motion I'm sure

[Todd88]

Homework Statement

A group of physics students are conducting an experiment in projectile motion. They want to launch a ball into a bucket that is 8 m away from their spring-loaded launcher. They have hypothesized that by setting their launcher to its long-range setting and placing the launcher barrel at a 35 degree angle that they can consistently hit the bucket when they fire the launcher. Ignoring air resistance, calculate the time of flight for the ball in their experiment.

Homework Equations

x=x0+V0xt
Vy=V0y-gt
y=y0+V0yt-1/2gt^2
x=(V0cos(theta))t
y=(V0sin(theta))t-1/2gt^2
Vx=V0cos(theta)0
Vy=V0sin(theta)-gt

The Attempt at a Solution

Not sure but I know this is simple. I am just brain dead right now because I am really sick but I need to get this done for tomorrow. I think you find the time using the y-components...

 

[LowlyPion]

You know the angle θ. You know that Vox = 8m / T = Vo*Cos35

You also know that VoSinθ is vertical velocity.

From V = Vo - g*T

you know then that time of flight is

VoSin35 - g*T/2 = -VoSin35 or T = 2VoSin35/g

Since T in both equations is equal then you can determine Vo and then you can figure the total time.