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Simple proof of Boolean Algebra

  1. Jan 30, 2010 #1
    1. The problem statement, all variables and given/known data
    Prove (x+y)(y+z)(x'+z) = (x+y)(x'+z)

    2. Relevant equations

    3. The attempt at a solution

    On LHS, i have done till

    =(y+xz)(x'+z) 1st- distributive

    =x'y+yz+xz 2nd- distributive(2ce)

    =(x+y)(x'+z) 3rd-?

    For third procedure, what properties should be used?
    I think it could be done in one step but i can't figure it out...

    Could someone please help me out here?
  2. jcsd
  3. Jan 31, 2010 #2


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    Add xx' so you can factor it. It won't change anything since xx'=0.
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