Simple Question about the direction of magnetic induction

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Homework Help Overview

The discussion revolves around a problem involving electromagnetic induction, specifically focusing on the induced electromotive force (emf) in a copper wire moving through a magnetic field. The magnetic field strength is given as 0.02 Tesla, and the wire's orientation and movement direction are central to the inquiry about the location of induced positive charge.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of induced emf using the formula V = BLV and question how to determine the location of induced positive charge. There are attempts to clarify the application of the Lorentz law and its implications for charge movement. Some participants express uncertainty about the correctness of the calculated emf and the interpretation of directions.

Discussion Status

The conversation is ongoing, with participants providing insights and questioning each other's reasoning. There is a mix of confirmations and challenges regarding the calculations and interpretations of the problem setup. Some guidance has been offered on using vector expressions to analyze the situation further.

Contextual Notes

There are indications of potential miscommunication regarding the wire's orientation and the translation of terms, which may affect the understanding of the problem. Participants are also navigating the implications of different orientations of the wire in relation to the magnetic field and velocity.

titansarus
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Homework Statement


There is a magnetic field B=0.02 Tesla and its direction is toward the plane (perpendicular to plane, shown by X X X X X - I'm not sure how to say this direction in English,sorry). we have a copper wire (uniform bar) perpendicular to magnetic field from south to north. we move the wire with speed 8 m/s from west to east. We want to find the induced emf and the place where the positive charge is induced (north or south)

Length of wire=0.25 m
2. The attempt at a solution
I can calculate the first part easily with V = BLV and we get 0.04 volt. But I don't know how to determine the place where the positive charge is induced. How I should solve this?

Thanks in advance and sorry for my English.
 
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titansarus said:

Homework Statement


There is a magnetic field B=0.02 Tesla and its direction is toward the plane (perpendicular to plane, shown by X X X X X - I'm not sure how to say this direction in English,sorry). we have a copper wire (uniform bar) perpendicular to magnetic field from south to west. we move the wire with speed 8 m/s from west to east. We want to find the induced emf and the place where the positive charge is induced (north or south)2. The attempt at a solution
I can calculate the first part easily with V = BLV and we get 0.04 volt. But I don't know how to determine the place where the positive charge is induced. How I should solve this?

Thanks in advance and sorry for my English.
You didn't give L so we can't confirm your answer of 0.04V.

To get the charge locations, use the Lorentz law.
 
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rude man said:
You didn't give L so we can't confirm your answer of 0.04V.

To get the charge locations, use the Lorentz law.
Sorry, The L is 0.25 meter. Can you give more information about how to use lorentz law (If you mean F = q v cross b). It gives the force, how can I get the position of positive charge with that?
 
titansarus said:
Sorry, The L is 0.25 meter. Can you give more information about how to use lorentz law (If you mean F = q v cross b). It gives the force, how can I get the position of positive charge with that?
Charge goes in the direction of force does it not?
Your answer is incorrect. Think about tthe direction of the bar in relation to the direction of the velocity.
 
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rude man said:
Charge goes in the direction of force does it not?
Your answer is incorrect. Think about tthe direction of the bar in relation to the direction of the velocity.
The direction of force for q>0 is to north. so it means that positive charge goes to north,yes?

But I think v=0.04 volt is correct, Are you sure it is incorrect?
 
titansarus said:
The direction of force for q>0 is to north. so it means that positive charge goes to north,yes?
You must decide for yourself.
But I think v=0.04 volt is correct, Are you sure it is incorrect?
If the direction of the bar were east-west, i.e. along v, what would the emf be then?
 
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rude man said:
You must decide for yourself.
If the direction of the bar were east-west, i.e. along v, what would the emf be then?
Oh, the main question was in another language and I mistranslated it. It was meant to be south-north. for south-west, it is sqrt(2) * 0.02, and for east-west, 0, yes?
 
titansarus said:
Oh, the main question was in another language and I mistranslated it. It was meant to be south-north. for south-west, it is sqrt(2) * 0.02, and for east-west, 0, yes?
Carry out the vector expression emf = B⋅(L x v). (This also answers your first question).
 

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