In a reversed heat engine, the work done on the engine is 85 kJ and the heat transfer to the engine from the low temperature region is 260 kJ. Determine:
1. the heat transfer to the high temperature region
2. the coefficient of performance as a refrigerator
Q(hot) + Q(cold) + W = 0
The Attempt at a Solution
260 + 85 = 345 kJ for question 1 if I am correct.
COP = W / Q(input) = 260 / (345-260) =3.05