(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Cliff and Will are carrying a uniform 2.0 m board of mass 71 kg. Will is supporting the board at the end while Cliff is 0.6 m from the other end as shown. Cliff has attached his lunch to the end of the board, and the tension in the string supporting the lunch is 200 N.

A) Find the force that Cliff exerts on the board.

B) Find the force that Will exerts on the board.

2. Relevant equations

3. The attempt at a solution

It seems easy enough, I will set Will's Normal force to be the pivot point and solve for Cliff's.

[tex](1.4m)N_{Cliff} = (200N)(2m) + (710N)(1m)[/tex]

[tex]N_{Cliff}\approx 793N[/tex]

To find Will's, I will subtract the Cliff's (793N) from the total (1110N) to get 317N.

I then wanted to check my answer by solving for Will's by using Cliff as the pivot point, but came up with different numbers.

[tex]N_{Will}(1.4m)=(200N)(.6m) + (710N)(.4m)[/tex]

[tex]N_{Will}\approx 289N[/tex]

Where did I go wrong?

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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