# Torque - Lady on a diving board

1. Apr 8, 2009

### tascja

1. The problem statement, all variables and given/known data
A woman whose weight is w = 500 N is poised at the right end of a diving board with a length of Lw = 3.90 . The board has negligible weight and is bolted down at the left end, while being supported L2 = 1.40 m away by a fulcrum, as figure shows. Find Forces F1 and F2 that the
bolt and the fulcrum, respectively, exert on the board.

2. Relevant equations
T= rFsin(theta)

3. The attempt at a solution
Since there are two unknown forces, can i solve for them separately, assuming the axis of rotation is different in each?
to solve for F1 i would have that the fulcrum in the axis of rotation, assuming F2 is 0 for acting on the axis of rotation. and for F2 i would have the fulcrum at the bolt...

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2. Apr 10, 2009

### method_man

You can calculate momentuma around bolt.
ΣM=0 F2*1,4 - w*3.9=0
F2=w*3.9/1,4
After you get F2, you can easily calculate F1:F1=F2 - w