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Torque - Lady on a diving board

  1. Apr 8, 2009 #1
    1. The problem statement, all variables and given/known data
    A woman whose weight is w = 500 N is poised at the right end of a diving board with a length of Lw = 3.90 . The board has negligible weight and is bolted down at the left end, while being supported L2 = 1.40 m away by a fulcrum, as figure shows. Find Forces F1 and F2 that the
    bolt and the fulcrum, respectively, exert on the board.

    2. Relevant equations
    T= rFsin(theta)

    3. The attempt at a solution
    Since there are two unknown forces, can i solve for them separately, assuming the axis of rotation is different in each?
    to solve for F1 i would have that the fulcrum in the axis of rotation, assuming F2 is 0 for acting on the axis of rotation. and for F2 i would have the fulcrum at the bolt...
     

    Attached Files:

  2. jcsd
  3. Apr 10, 2009 #2
    You can calculate momentuma around bolt.
    ΣM=0 F2*1,4 - w*3.9=0
    F2=w*3.9/1,4
    After you get F2, you can easily calculate F1:F1=F2 - w
     
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