Torque - Lady on a diving board

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SUMMARY

The discussion focuses on calculating the forces exerted by a bolt and a fulcrum on a diving board with a woman weighing 500 N positioned at the end. The board is 3.90 m long and supported 1.40 m from the left end by a fulcrum. Using the torque equation T = rFsin(theta), the forces F1 and F2 can be determined by setting the sum of moments around the fulcrum to zero. The calculations yield F2 = (500 N * 3.90 m) / 1.40 m and F1 = F2 - 500 N.

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Homework Statement


A woman whose weight is w = 500 N is poised at the right end of a diving board with a length of Lw = 3.90 . The board has negligible weight and is bolted down at the left end, while being supported L2 = 1.40 m away by a fulcrum, as figure shows. Find Forces F1 and F2 that the
bolt and the fulcrum, respectively, exert on the board.

Homework Equations


T= rFsin(theta)

The Attempt at a Solution


Since there are two unknown forces, can i solve for them separately, assuming the axis of rotation is different in each?
to solve for F1 i would have that the fulcrum in the axis of rotation, assuming F2 is 0 for acting on the axis of rotation. and for F2 i would have the fulcrum at the bolt...
 

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tascja said:

Homework Statement


A woman whose weight is w = 500 N is poised at the right end of a diving board with a length of Lw = 3.90 . The board has negligible weight and is bolted down at the left end, while being supported L2 = 1.40 m away by a fulcrum, as figure shows. Find Forces F1 and F2 that the
bolt and the fulcrum, respectively, exert on the board.
You can calculate momentuma around bolt.
ΣM=0 F2*1,4 - w*3.9=0
F2=w*3.9/1,4
After you get F2, you can easily calculate F1:F1=F2 - w
 

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