Simple rotational motion problem

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SUMMARY

The discussion centers on the rotational motion of two identical merry-go-rounds, one heavily loaded with children and the other nearly empty. Both merry-go-rounds are subjected to the same frictional forces and initial speeds. The consensus is that the merry-go-round with the greater mass, due to the presence of children, will take longer to stop because it possesses greater angular momentum, necessitating more force to bring it to a halt.

PREREQUISITES
  • Understanding of rotational motion principles
  • Familiarity with angular momentum concepts
  • Basic knowledge of frictional forces
  • Concept of moment of inertia
NEXT STEPS
  • Research the relationship between mass and angular momentum in rotational systems
  • Study the effects of friction on rotating bodies
  • Explore calculations involving moment of inertia for various shapes
  • Learn about energy conservation in rotational motion
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Physics students, educators, and anyone interested in understanding the dynamics of rotational motion and the effects of mass on stopping time.

kirby27
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Two identical merry-go-rounds are rotating at the same speed. One is crowded with riding children; the other is nearly empty.

If both merry-go-rounds cut off their motors at the same time and coast to a stop, slowed only by friction (which you can assume is the same for both merry-go-rounds), which will take longer to stop?

i think the one with the people will take longer to stop because they have the same moment of inertia but the mass of the people one is larger.
 
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I'd agree with you. If the force of friction is the same, and the speed is the same, the heavier merry-go-round will have more angular momentum. Therefore it will take more force to stop it.
 

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