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Simple Sine lim Understanding question

  1. Jan 22, 2010 #1
    1. The problem statement, all variables and given/known data
    prove lim h-->0 sin(h)/h = 1

    2. Relevant equations
    I understand the idea of squeze theorom. Understand that area of small triangle < sector area< big triangle. I know 1/2sin(h) < 1/2h < 1/2(sin(h)/cos(h)). In my calc book it goes from sinh< h< (sinh/cosh) to cos(h)/sin(h)< 1/h <1/sin(h). How does this happen?

    3. The attempt at a solution

    multiply outside by cos(h) but inside is just reciprocal.
    Last edited: Jan 22, 2010
  2. jcsd
  3. Jan 22, 2010 #2


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    If you have two positive numbers with a<b, then 1/a>1/b.
  4. Jan 22, 2010 #3
    Thank You :-)
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