1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Limit proof of trigonometric function

  1. Jun 17, 2012 #1
    1. The problem statement, all variables and given/known data

    Prove that limh→0[(cos(h-1))/h]=0.

    2. Relevant equations

    Half angle formula
    From an example:

    limh→0[(cos(h-1))/h] = limh→0[-(2sin2(h/2))/h]

    They state that they use the half-angle formula in the following way:

    cosh= 1-2sin2(h/2)

    I'm not really sure how they are getting this from the half angle formula. Any pointer in the correct direction would be greatly appreciated. Thank you, in advance.
  2. jcsd
  3. Jun 17, 2012 #2


    User Avatar
    Homework Helper
    Gold Member
    2017 Award

    Well known identity: cos(a + b) = cos(a)cos(b) - sin(a)sin(b)

    Write cos(h) = cos(h/2 + h/2) and use the identity above along with cos2θ + sin2θ = 1
  4. Jun 18, 2012 #3
    Thank you, very much! Somehow I didn't notice to split cos(h) into cos(h/2 + h/2).
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Limit proof of trigonometric function