Simple supported round shaft deflection

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SUMMARY

The discussion focuses on calculating the deflection of a 1.938" diameter steel shaft supported at both ends under various loads. The formula provided for maximum deflection in a simply supported beam is δ = 5wL4/(384EI), where E is Young's modulus (29 x 106 lbs/in2 for steel) and I is the second moment of area (πD4/64). Specific deflections requested include 300 lbs for 24", 450 lbs for 36", and 600 lbs for 48" lengths. Proper unit usage is emphasized for accurate calculations.

PREREQUISITES
  • Understanding of beam deflection principles
  • Familiarity with Young's modulus and material properties
  • Knowledge of the second moment of area for circular shafts
  • Basic proficiency in unit conversions and calculations
NEXT STEPS
  • Research the application of the beam deflection formula in engineering contexts
  • Learn about different materials' Young's modulus values for comparative analysis
  • Explore the significance of the second moment of area in structural engineering
  • Investigate software tools for beam deflection analysis, such as MATLAB or SolidWorks
USEFUL FOR

Mechanical engineers, structural engineers, and students studying materials and mechanics will benefit from this discussion, particularly those focused on beam design and deflection analysis.

AQUAPOP
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Hello.
I'm looking for the deflections of a 1.938" dia. steel shaft at different lengths.
Supported in bearings at both ends.
150lbs. per foot of length, with all of the weight in the center of the rod.
I.E. how much does the rod deflect of there is 450lbs. pushing down between 36"...
I'm looking for 300 lbs. for 24", 450 for 36", and 600 for 48".

Thanks in advance,
Frank
 
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AQUAPOP said:
Hello.
I'm looking for the deflections of a 1.938" dia. steel shaft at different lengths.
Supported in bearings at both ends.
150lbs. per foot of length, with all of the weight in the center of the rod.
I.E. how much does the rod deflect of there is 450lbs. pushing down between 36"...
I'm looking for 300 lbs. for 24", 450 for 36", and 600 for 48".

Thanks in advance,
Frank

For a simply supported beam, the max deflection for an evenly distributed load is

δ = 5wL[itex]^{4}[/itex]/(384EI)

where:
L - distance between supports, in inches
w - distributed load, in pounds / inch
E - Young's modulus for the shaft material
(for example, for steel, E = 29*10[itex]^{6}[/itex] lbs/in[itex]^{2}[/itex])
I - second moment of area for the shaft, in inches[itex]^{4}[/itex]

I for a circular shaft is πD[itex]^{4}[/itex]/64, D - diameter in inches
δ - shaft deflection, in inches
π - constant = 3.14159

Make sure you use the correct units and you are good to go.
 
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