Simplification of Log/Exponent Expression

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SUMMARY

The discussion focuses on simplifying the expression [log_3(2^x) * 3^(2x)]/e^(2lnx). The participant correctly identifies that e^(2lnx) simplifies to x^2 and log_3(2^x) simplifies to x*log_3(2). The final expression is simplified to [3^(2x)/x] * log_3(2). The participant expresses uncertainty about further simplification, particularly regarding the relationship between 3^(2x) and log_3(2).

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Homework Statement



Simplify the following:

[log_3(2^x) * 3^(2x)]/e^(2lnx)

The Attempt at a Solution



e^(2lnx) = x^2
Log_3(2^x) = xlog_3(2)

Thus:

= 3^(2x)*x*log_3(2) / x^2
= [3^(2x)/x] * log_3(2)

Am I missing anything here? I don't seem to find anyway to continue simplification, although the 3^2x seems like a weird choice if I cannot somehow use log_3(2) with it.
 
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Hi moo5003! :smile:
moo5003 said:
Am I missing anything here?

Looks fine to me! :smile:

(apart from being difficult to read, that is :rolleyes: … try using the X2 and X2 tags just above the Reply box :wink:)
 

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