Simplified Limit Calculation for (1-e^(1-x/(1+x))x)/(1/x)

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Homework Help Overview

The discussion revolves around the limit calculation of the expression (1-e^(1-x/(1+x))x)/(1/x). Participants are exploring the simplification and evaluation of this limit, which involves concepts from calculus and exponential functions.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of L'Hôpital's rule and the expansion of logarithmic functions. There is an emphasis on identifying components of the expression and how to manipulate them for simplification.

Discussion Status

There is ongoing exploration of various approaches, including the use of logarithmic identities and expansions. Some participants express confusion and seek clarification on specific steps, indicating a collaborative effort to understand the problem better.

Contextual Notes

Participants mention the need for clarity in their expressions and reasoning, highlighting the importance of showing work to facilitate discussion. There are references to forum rules regarding the sharing of solutions, emphasizing the learning process over immediate answers.

Physics lover
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Homework Statement
Problem-:
Lim x(1/e-(x/(1+x))^x)
Where x tends to infinity
Relevant Equations
L'Hospitale
I simplified somewhat and got (1/e-(1-x/(1+x))x)/(1/x)
So i can't find that it is 0/0 form so tried by applyying L'Hospitale,But it just became complicated.So need help.
 
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Use that ##a^x = \exp(x \ln(a))## and start expanding the log in powers of ##1/x##.
 
Orodruin said:
Use that ##a^x = \exp(x \ln(a))## and start expanding the log in powers of ##1/x##.
Can you explain a little more.I think my a here is ##x/(1+x)##.But what will i do with the x that is outside the bracket.
 
I suggest you start the way I suggested. The rest will follow.
 
Orodruin said:
I suggest you start the way I suggested. The rest will follow.
But i didn't got what you said.Please explain a little more.
 
You were correct in identifying ##a##, now what do you get when you use that on your expression? I need to see how far you have gotten to be able to help you.
 
Orodruin said:
You were correct in identifying ##a##, now what do you get when you use that on your expression? I need to see how far you have gotten to be able to help you.
Ok after then i opened the expansion of ln(##x##/##(1+x)##).But i got stuck afterwards.
 
Physics lover said:
Ok after then i opened the expansion of ln(##x##/##(1+x)##).But i got stuck afterwards.
It's really unhelpful to say, "I did X and then I got stuck." What you mean by X and what we think you meant by X could be entirely different. Please show your work.
 
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Please show the entire expression that you have and what your thoughts are about it, i.e., why are you stuck?
 
  • #10
Ok so here is my try
246083


Now shall i use L'Hospitale from here or something else.
 
  • #11
I suggest that you use that ##\ln(a/b) = - \ln(b/a)## and do some rewriting of that logarithm.
 
  • #12
Orodruin said:
I suggest that you use that ##\ln(a/b) = - \ln(b/a)## and do some rewriting of that logarithm.
Thanks i got the answer.
 
  • #13
Physics lover said:
Thanks i got the answer.
Would you mind sharing? Forum rules prevents others from posting solutions until the questioner has shown their solution and it may be of use to others finding this thread.
 
  • #14
Orodruin said:
Would you mind sharing? Forum rules prevents others from posting solutions until the questioner has shown their solution and it may be of use to others finding this thread.
Ok
246095

Here is my solution.Is it ok?
 
  • #15
Physics lover said:
Ok
View attachment 246095
Here is my solution.Is it ok?
what theory? What chapter of math?
 

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