Simplify each of this following surd

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Homework Help Overview

The discussion revolves around simplifying a series of surds, specifically the expression 3∜2 - ∜(2/81) + ∜32 - ∜162. Participants are exploring the simplification of these surds and clarifying the transformations involved.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to simplify the expression and clarify the transformations made, particularly questioning the origin of certain terms like 130. There is an exploration of prime factorization as a method for simplification.

Discussion Status

The discussion is active, with participants providing insights into the simplification process and questioning assumptions about the transformations. Some guidance has been offered regarding the correct approach to simplifying specific surds.

Contextual Notes

There is confusion regarding the calculations and transformations of the surds, particularly with the expression involving 130 and the simplification of ∜(2/81). Participants are also addressing the importance of correct mathematical properties in simplification.

jonathan22
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Homework Statement


3∜2 - ∜(2/81) + ∜32 - ∜162

Homework Equations

The Attempt at a Solution


3∜2 - ∜(2/81) - ∜130
3∜2 – ∜2/3 - ∜130
exactly when i tried to calculate, i got problem with the next of this calculating, i confused. Can anybody help me for do the next of this calculating??[/B]
 
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Where does the 130 come from? That looks like an incorrect transformation.

Did you split the numbers in the square roots into their prime factors?
 
oh i wrong, i mean 3∜2 - ∜(2/81) - ∜130
3∜2 – ∜2/3 - ∜130, and then the 130 come from 32-162
 
jonathan22 said:

Homework Statement


3∜2 - ∜(2/81) + ∜32 - ∜162

jonathan22 said:
oh i wrong, i mean 3∜2 - ∜(2/81) - ∜130
3∜2 – ∜2/3 - ∜130, and then the 130 come from 32-162

First off, 32 - 162 = -130. More importantly, ##\sqrt[4]{a} - \sqrt[4]{b} \ne \sqrt[4]{a - b}##.
As already mentioned simpligy ##\sqrt[4]{162}## by factoring 162 into its prime factors.
 
ok, but how to solve ∜(2/81)?
 
That part was right. $$ \frac{\sqrt[4]2}{3}$$
 
It helps to know that [itex]81= 3^4[/itex] and [itex]162= 2(3^4)[/itex].
 

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