1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Simplify each expression: 2(4-h)^2-32/h

  1. Aug 28, 2011 #1
    1. The problem statement, all variables and given/known data
    simplify each expression: 2(4-h)^2-32/h

    2. Relevant equations

    3. The attempt at a solution

    I forget if I should multiply the 2 into the 4-h.
  2. jcsd
  3. Aug 28, 2011 #2
    you can't multiply the 2 into the 4-h until you square the 4-h.
    Remember to do (4-h)(4-h).
  4. Aug 28, 2011 #3
    ok with this I eventually got -2(h^2+4h+12)/h , but I feel like I did something wrong.
  5. Aug 28, 2011 #4
    was the original expression [tex] \frac{2(4-h)^2-32}{h} [/tex]


    [tex] 2(4-h)^2-\frac{32}{h} [/tex]?
  6. Aug 28, 2011 #5
    Either way, make sure [tex] (4-h)(4-h)=16-8h+h^2 [/tex]
  7. Aug 28, 2011 #6
    would it just equal -16. Heres where I would have screwed up im at 2(16-8h+h^2)-32/h or would it be 2+16-8h+h^2-32/h
  8. Aug 28, 2011 #7
    it would be 2(16-8h+h^2)-32/h

    but I'm still not clear if its [tex] \frac{2(16-8h+h^2)-32}{h} [/tex]
    or [tex] 2(16-8h+h^2)-\frac{32}{h} [/tex]
  9. Aug 28, 2011 #8
    its the first one.
  10. Aug 28, 2011 #9
    okay, then distribute the 2, then cancel an h... and voila! :)
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Simplify each expression: 2(4-h)^2-32/h
  1. Simplifying a/(2^a) (Replies: 21)