Simplify each expression: 2(4-h)^2-32/h

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Homework Help Overview

The problem involves simplifying the expression 2(4-h)^2 - 32/h. Participants are exploring the correct approach to simplifying this algebraic expression.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss whether to multiply the 2 into (4-h) before squaring, and there is uncertainty about the correct interpretation of the expression regarding the placement of the fraction.

Discussion Status

There is active engagement with various interpretations of the expression, and some participants are providing guidance on the order of operations and distribution. However, there is no explicit consensus on the final form of the expression being simplified.

Contextual Notes

Participants are considering two possible interpretations of the expression, which affects how they approach the simplification. There is also mention of potential mistakes in the simplification process.

davie08
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Homework Statement


simplify each expression: 2(4-h)^2-32/h


Homework Equations





The Attempt at a Solution



I forget if I should multiply the 2 into the 4-h.
 
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you can't multiply the 2 into the 4-h until you square the 4-h.
Remember to do (4-h)(4-h).
 
ok with this I eventually got -2(h^2+4h+12)/h , but I feel like I did something wrong.
 
was the original expression [tex]\frac{2(4-h)^2-32}{h}[/tex]

or

[tex]2(4-h)^2-\frac{32}{h}[/tex]?
 
Either way, make sure [tex](4-h)(4-h)=16-8h+h^2[/tex]
 
would it just equal -16. Heres where I would have screwed up I am at 2(16-8h+h^2)-32/h or would it be 2+16-8h+h^2-32/h
 
it would be 2(16-8h+h^2)-32/h

but I'm still not clear if its [tex]\frac{2(16-8h+h^2)-32}{h}[/tex]
or [tex]2(16-8h+h^2)-\frac{32}{h}[/tex]
 
its the first one.
 
okay, then distribute the 2, then cancel an h... and voila! :)
 

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