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Simplify each expression: 2(4-h)^2-32/h

  1. Aug 28, 2011 #1
    1. The problem statement, all variables and given/known data
    simplify each expression: 2(4-h)^2-32/h


    2. Relevant equations



    3. The attempt at a solution

    I forget if I should multiply the 2 into the 4-h.
     
  2. jcsd
  3. Aug 28, 2011 #2
    you can't multiply the 2 into the 4-h until you square the 4-h.
    Remember to do (4-h)(4-h).
     
  4. Aug 28, 2011 #3
    ok with this I eventually got -2(h^2+4h+12)/h , but I feel like I did something wrong.
     
  5. Aug 28, 2011 #4
    was the original expression [tex] \frac{2(4-h)^2-32}{h} [/tex]

    or

    [tex] 2(4-h)^2-\frac{32}{h} [/tex]?
     
  6. Aug 28, 2011 #5
    Either way, make sure [tex] (4-h)(4-h)=16-8h+h^2 [/tex]
     
  7. Aug 28, 2011 #6
    would it just equal -16. Heres where I would have screwed up im at 2(16-8h+h^2)-32/h or would it be 2+16-8h+h^2-32/h
     
  8. Aug 28, 2011 #7
    it would be 2(16-8h+h^2)-32/h

    but I'm still not clear if its [tex] \frac{2(16-8h+h^2)-32}{h} [/tex]
    or [tex] 2(16-8h+h^2)-\frac{32}{h} [/tex]
     
  9. Aug 28, 2011 #8
    its the first one.
     
  10. Aug 28, 2011 #9
    okay, then distribute the 2, then cancel an h... and voila! :)
     
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