Simplifying an Expression: (2x^2-3x+1)(4)(3x+2)^3(3)+(3x+2)^4(4x-3)

Click For Summary

Homework Help Overview

The discussion revolves around simplifying a mathematical expression involving polynomial multiplication and factoring. The expression in question is: (2x^2-3x+1)(4)(3x+2)^3(3)+(3x+2)^4(4x-3).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand the process of simplifying the expression and has noted a final answer but seeks clarification on how to arrive at it. Some participants suggest using factorization techniques and exploring common factors within the expression.

Discussion Status

Participants are actively engaging with the problem, with one suggesting a potential simplification by factoring out a common term. There is an ongoing exploration of factorization methods and how they apply to the given expression.

Contextual Notes

The original poster is preparing for a quiz and is under time constraints, which may influence the urgency of their request for help. There is also a mention of needing to understand the basic principles of factorization.

Cornraker
Messages
24
Reaction score
0

Homework Statement



I have a quiz tomorrow and i know a problem like this is going to be on it and i need to figure out the process

Homework Equations



the expression is: (2x^2-3x+1)(4)(3x+2)^3(3)+(3x+2)^4(4x-3)

The Attempt at a Solution



i know the final answer(3x+2)^3(36x^2-37x+6)

Ive tried to work the problem several times and i can't figure out how it turns out to be this. can somebody please do a step by step. it would be greatly appreciated.
 
Physics news on Phys.org
Sure thing. (by the way you should have called it factorizing an expression :-p)

You need to have the basic idea of factorizing deeply embedded into your head. Mainly, ab+ac=a(b+c) (1). a,b and c could be anything much more complicated.

Lets take a=x^2(x+1)^2

Then we would need to factorize x^2(x+1)^2b+x^2(x+1)^2c

Can you now see how we can factorize out the a (or in this case the x^2(x+1)^2) ? We now get the same thing as in (1): a(b+c)=x^2(x+1)^2(b+c)

At the same time, b and c can be something more complicated as well. If we let b=x(x+1) and c=x+1 then we now have:

a\left(x(x+1)+(x+1)\right) but this time we aren't completely done because b and c have a common factor also. x(x+1)+(x+1)=x(x+1)+1(x+1)=(x+1)(x+1)=(x+1)^2

So let's put it all together now in ab+ac=a(b+c) where a=x^2(x+1)^2, b=x(x+1), c=x+1

x^2(x+1)^2(x(x+1)+(x+1))=x^2(x+1)^2(x+1)^2=x^2(x+1)^4 This last form is completely factorized.


Now looking at your expression: let some other variable such as y=(3x+2)^3 and see if that makes things easier to factorize. Also you'll need to factorize 2x^2-3x+1, can you do this?
 
well i'll sure try to do it. thank you very much for your time and this lengthy explanation!
 
i think i got it! if I'm correct i can factor out a (3x+2)^3 and that makes thing a whole lot simpler
 
Cornraker said:
well i'll sure try to do it. thank you very much for your time and this lengthy explanation!
No problem! :smile:

Cornraker said:
i think i got it! if I'm correct i can factor out a (3x+2)^3 and that makes thing a whole lot simpler
Yep :wink:
 

Similar threads

Replies
4
Views
3K
Replies
19
Views
3K
Replies
3
Views
2K
Replies
2
Views
2K
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
8
Views
2K
Replies
14
Views
2K
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K