Simplifying Derivatives: Solving for Constants in f'(x) = [(x+c)/(mx+n)]p

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SUMMARY

The discussion focuses on simplifying the derivative of the function f(x) = sqrt(4-x²) + 2cos⁻¹(x/2) into the form -[(x+c)/(mx+n)]p. The derivative is calculated as -x/sqrt(4-x²) - 1/sqrt(1-(x/2)²). Participants emphasize the need to manipulate the derivative further to identify the constants c, m, n, and p, with suggestions to multiply by a factor to facilitate simplification.

PREREQUISITES
  • Understanding of calculus, specifically derivatives
  • Familiarity with inverse trigonometric functions, particularly cos⁻¹(x)
  • Knowledge of algebraic manipulation techniques
  • Ability to work with square roots and rational expressions
NEXT STEPS
  • Study the process of simplifying derivatives in calculus
  • Learn about algebraic manipulation of rational expressions
  • Explore the properties of inverse trigonometric functions
  • Review techniques for finding constants in derivative forms
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Students studying calculus, particularly those tackling derivative simplification, and educators looking for examples of inverse trigonometric function applications.

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Homework Statement



Let f(x) = sqrt(4-x2) + 2cos-1(x/2)

Then f '(x) can be written in simplified form -[(x+c)/(mx+n)]p
NOTE: I'm not sure if that negative is supposed to be there since my book is smudged.

What are the values of c, m, n, and p?


Homework Equations



Derivative of cos-1(x) is -1/(sqrt(1-x2)

The Attempt at a Solution



I found the derivative to be -x/sqrt(4-x2) - 1/sqrt(1-(x/2)2)

My problem is that I have no idea how to simplify it into that form. Can anyone offer me some assistance on this question?

Thanks in advance!
 
Physics news on Phys.org
Try multiplying [tex]-\frac{1}{\sqrt{1-(\frac{x}{2})^{2}}}\cdot\frac{2}{2}[/tex]
 

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