Simplifying Equation With Square Root

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Homework Help Overview

The discussion revolves around simplifying an equation involving a square root, specifically the equation (c - 18)² = (-3√c)². Participants are examining the steps taken to simplify this equation and the implications of their calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the correct application of squaring terms and the expansion of binomials. There are attempts to clarify misconceptions about squaring negative numbers and the proper use of the FOIL method. Some participants express their struggles with foundational math concepts and seek guidance on improving their understanding.

Discussion Status

The discussion is ongoing, with participants providing clarifications and corrections to each other's misunderstandings. There is a recognition of the need to understand quadratic equations better, and some participants are exploring the implications of coefficients in the context of the quadratic formula.

Contextual Notes

One participant mentions their background in math and the challenges faced in transitioning to higher-level courses, indicating a need for foundational support in algebra and related subjects.

kwikness
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Homework Statement


An equation in a book lists this equation:
(c - 18)[tex]^{2}[/tex] = (-3[tex]\sqrt{c})[/tex][tex]^{2}[/tex]

And it simplifies it as:
c[tex]^{2}[/tex] -45c + 324 = 02. The attempt at a solution
When I do out the equation, I get:
c[tex]^{2}[/tex] + 324 = 9 + c

i squared c, then -18 for the left side of the equation, then for the right side, I squared -3 to get 9, then [tex]\sqrt{c}[/tex], which is c.
 
Last edited:
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Hi kwikness and welcome to PF,

Firstly, note that;

[tex]\left(a+b\right)^2 \neq a^2+b^2[/tex]

Rather,

[tex]\left(a+b\right)^2 = \left(a+b\right)\cdot\left(a+b\right) = a^2 +2ab + b^2[/tex]

Secondly,

[tex](-3)^2 \neq 324[/tex]

And thirdly;

[tex](a\cdot b)^2 \neq a^2+b^2[/tex]

Rather,

[tex](a\cdot b)^2 = a^2\cdot b^2[/tex]
 
Last edited:
I squared -3 to get 324
Sorry, I meant 9 =)

I made my mistake when I forgot to "FOIL" the left-hand side of the equation. When I do so, I get:

C[tex]^{2}[/tex] -45c + 324 = 0

Thank you very much for clearing that up for me. I'm in a bit of a situation. I'm a good student in my 4th semester of college. In high school, I was able to slide by my math classes. I half-assed Algebra I, did okay in Geometry, and took no other math courses. Now I find myself in Calculus I, 5 years after my last math class. The first thing my professor said was, "You're not going to pass this course unless you've had Trigonometry and Pre-Calculus.", which I haven't. I'm now trying to backtrack and learn these courses myself with the aid of video tutorials and practicing problems on my own time. I excel in every subject at school but math. It's such a weakness for me and I'm now just starting to do something about it.

Any pointers are appreciated, thanks again for your help.
 
One needs to know the solution to the quadratic equation.

Alternatively, one recognizes (c+a)(c+b) = c2 + (a+b)c + ab = c2 - 45c + 324, so what does one do with corresponding coefficients?
 

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