MHB Simplifying exponential expressions

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The discussion focuses on simplifying the expression 8p^-3 x (4p^2)^-2/p^-5. The initial approach involved flipping the negative exponents, leading to an incorrect simplification. It was clarified that the 8 should remain in the numerator since it does not have a negative exponent, which affects the final result. After correcting the steps, the numerical part simplifies to 1/2, leading to the correct answer of 1/2p^2. The importance of accurately handling exponents in simplification is emphasized.
arl2267
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Simplify 8p-3 x (4p2)-2/p-5.

This is what I got:

First thing I did was flip everything to get rid of the negative exponents:

p5/8p3x(4p2)2

next thing I did was multiply the 4p2 by 2

p5/ 8p3x16p4Then I subtracted thep5 from the 8p3

p2/8x16p4

and ended up with

1/128p2 I know that the answer is 1/2p2​ so where did I go wrong?
 
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After expanding the brackets

$\displaystyle \frac{8p^{-3}\times 4^{-2}\times p^{-4}}{p^{-5}}$

$\displaystyle \frac{8p^{-3}\times p^{-4}}{4^{2}\times p^{-5}}$

You can now see the numerical part is $\displaystyle\frac{8}{16}= \frac{1}{2}$
 
In your first step where you "flip" everything, you cannot do this with the 8 since it does not have a negative exponent. If you had left the 8 in the numerator, then you would have gotten the desired result.

edit: Welcome to the forum, and I certainly appreciate the fact that you show your work...this makes it much easier to address where your error(s) may be.:cool:
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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