MHB Simplifying exponential expressions

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The discussion focuses on simplifying the expression 8p^-3 x (4p^2)^-2/p^-5. The initial approach involved flipping the negative exponents, leading to an incorrect simplification. It was clarified that the 8 should remain in the numerator since it does not have a negative exponent, which affects the final result. After correcting the steps, the numerical part simplifies to 1/2, leading to the correct answer of 1/2p^2. The importance of accurately handling exponents in simplification is emphasized.
arl2267
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Simplify 8p-3 x (4p2)-2/p-5.

This is what I got:

First thing I did was flip everything to get rid of the negative exponents:

p5/8p3x(4p2)2

next thing I did was multiply the 4p2 by 2

p5/ 8p3x16p4Then I subtracted thep5 from the 8p3

p2/8x16p4

and ended up with

1/128p2 I know that the answer is 1/2p2​ so where did I go wrong?
 
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After expanding the brackets

$\displaystyle \frac{8p^{-3}\times 4^{-2}\times p^{-4}}{p^{-5}}$

$\displaystyle \frac{8p^{-3}\times p^{-4}}{4^{2}\times p^{-5}}$

You can now see the numerical part is $\displaystyle\frac{8}{16}= \frac{1}{2}$
 
In your first step where you "flip" everything, you cannot do this with the 8 since it does not have a negative exponent. If you had left the 8 in the numerator, then you would have gotten the desired result.

edit: Welcome to the forum, and I certainly appreciate the fact that you show your work...this makes it much easier to address where your error(s) may be.:cool:
 

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