MHB Simplifying f(a+h)=-5(a+h)^2+2(a+h)-1

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The discussion focuses on the expansion of the function f(a+h) = -5(a+h)^2 + 2(a+h) - 1, specifically addressing the origin of the term 2ah in the expansion process. Participants clarify that when squaring a binomial, the correct formula is (x+y)^2 = x^2 + 2xy + y^2, which leads to the inclusion of the 2ah term. The conversation emphasizes the importance of treating the entire binomial as a single entity when applying exponentiation, rather than squaring individual terms. This common misunderstanding is referred to as the "freshman's dream," highlighting a frequent error among students.

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Rujaxso
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Not sure where the 2ah is coming from in the middle step.

f(a+h)=-5(a+h)^2+2(a+h)-1 = -5(a^2 + 2ah +h^2) +2a +2h -1 = -5a^2 - 10ah -5h^2 +2a +2h -1

Please enlighten me
 
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Rujaxso said:
Not sure where the 2ah is coming from in the middle step.

f(a+h)=-5(a+h)^2+2(a+h)-1 = -5(a^2 + 2ah +h^2) +2a +2h -1 = -5a^2 - 10ah -5h^2 +2a +2h -1

Please enlighten me

When you square a binomial, the following rule applies:

$$(x+y)^2=x^2+2xy+y^2$$

Have you seen this rule before?
 
Thanks Mark.
Nope I haven't, I was just going off of what I know about distributing.
 
And here is how you would do that distribution: $(a+ h)^2= (a+ h)(a+ h)= a(a+ h)+ h(a+ h)= a^2+ ah+ ha+ h^2= a^2+ 2ah+ h^2$.
 
Okay so instead of squaring each term I need to think about the quantity as a whole in the parenthesis as being a base for the exponent?
 
MarkFL said:
When you square a binomial, the following rule applies:

$$(x+y)^2=x^2+2xy+y^2$$

Have you seen this rule before?

Btw
Found this under Algebra 1 > polynomials > special products on khan academy, ...I will go over that section
 
Rujaxso said:
Okay so instead of squaring each term I need to think about the quantity as a whole in the parenthesis as being a base for the exponent?
Yes, that's what the parentheses mean. $( )^2$ means you square whatever is in the parentheses. $( )^3$ means you cube what ever is in the parentheses. $\sin( )$ means you take the sine of whatever is in the parentheses. In general $f( )$ means you apply the function f to whatever is in the parentheses.
 
I guess I wanted to apply A(B+C) = AB + AC to (B+C)^2 and make B^2 + C^2 which is incorrect I see.
 
Rujaxso said:
I guess I wanted to apply A(B+C) = AB + AC to (B+C)^2 and make B^2 + C^2 which is incorrect I see.

Thinking that:

$$(x+y)^n=x^n+b^n$$

is a mistake so commonly made by students, it's been given a name...the "freshman's dream." :)

I have also seen a lot of students make a related mistake, and that is to state:

$$\sqrt{x^2+y^2}=x+y$$
 

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