MHB Simplifying f(a+h)=-5(a+h)^2+2(a+h)-1

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The discussion centers on the confusion surrounding the term 2ah in the expression f(a+h)=-5(a+h)^2+2(a+h)-1. Participants clarify that when squaring a binomial, the correct expansion follows the formula (x+y)^2=x^2+2xy+y^2, which explains the presence of 2ah. One user admits to misunderstanding the squaring process by attempting to apply distribution incorrectly. The conversation highlights the importance of recognizing the entire binomial as a single entity when applying exponents. Overall, the thread emphasizes common misconceptions in algebra related to binomial expansion.
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Not sure where the 2ah is coming from in the middle step.

f(a+h)=-5(a+h)^2+2(a+h)-1 = -5(a^2 + 2ah +h^2) +2a +2h -1 = -5a^2 - 10ah -5h^2 +2a +2h -1

Please enlighten me
 
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Rujaxso said:
Not sure where the 2ah is coming from in the middle step.

f(a+h)=-5(a+h)^2+2(a+h)-1 = -5(a^2 + 2ah +h^2) +2a +2h -1 = -5a^2 - 10ah -5h^2 +2a +2h -1

Please enlighten me

When you square a binomial, the following rule applies:

$$(x+y)^2=x^2+2xy+y^2$$

Have you seen this rule before?
 
Thanks Mark.
Nope I haven't, I was just going off of what I know about distributing.
 
And here is how you would do that distribution: $(a+ h)^2= (a+ h)(a+ h)= a(a+ h)+ h(a+ h)= a^2+ ah+ ha+ h^2= a^2+ 2ah+ h^2$.
 
Okay so instead of squaring each term I need to think about the quantity as a whole in the parenthesis as being a base for the exponent?
 
MarkFL said:
When you square a binomial, the following rule applies:

$$(x+y)^2=x^2+2xy+y^2$$

Have you seen this rule before?

Btw
Found this under Algebra 1 > polynomials > special products on khan academy, ...I will go over that section
 
Rujaxso said:
Okay so instead of squaring each term I need to think about the quantity as a whole in the parenthesis as being a base for the exponent?
Yes, that's what the parentheses mean. $( )^2$ means you square whatever is in the parentheses. $( )^3$ means you cube what ever is in the parentheses. $\sin( )$ means you take the sine of whatever is in the parentheses. In general $f( )$ means you apply the function f to whatever is in the parentheses.
 
I guess I wanted to apply A(B+C) = AB + AC to (B+C)^2 and make B^2 + C^2 which is incorrect I see.
 
Rujaxso said:
I guess I wanted to apply A(B+C) = AB + AC to (B+C)^2 and make B^2 + C^2 which is incorrect I see.

Thinking that:

$$(x+y)^n=x^n+b^n$$

is a mistake so commonly made by students, it's been given a name...the "freshman's dream." :)

I have also seen a lot of students make a related mistake, and that is to state:

$$\sqrt{x^2+y^2}=x+y$$
 

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