Simplifying fractional indices

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SUMMARY

The discussion focuses on simplifying the expression $$10π \left( \frac V {4π} \right)^{2/3}$$ and clarifying the confusion between the variables v and V. Participants emphasized the importance of correctly handling the term $$10π$$ and demonstrated that it can be expressed as $$((10π)^{3/2})^{2/3}$$ for simplification. The conversation also highlighted the equivalence of $$ (a)^{\frac 2 3}$$ to $$ (a^2)^{\frac 1 3}$$ as a key step in the simplification process.

PREREQUISITES
  • Understanding of algebraic expressions and simplification techniques
  • Familiarity with fractional exponents and their properties
  • Basic knowledge of variable notation and the importance of consistency
  • Experience with mathematical equations involving π (pi)
NEXT STEPS
  • Study the properties of fractional exponents in detail
  • Learn about variable notation and its significance in mathematical expressions
  • Explore advanced algebraic simplification techniques
  • Investigate the applications of π in various mathematical contexts
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Students, educators, and anyone engaged in mathematical problem-solving, particularly those focusing on algebra and simplification techniques.

umzung
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Homework Statement
How do we simplify to the given expression?
Relevant Equations
$$10π \left( \frac v {4π} \right)^{2/3} = 5\sqrt[3] {{V^2}\frac π 2}$$
$$10π \left( \frac V {4π} \right)^{2/3} = 5\sqrt[3] {{V^2}\frac π 2}$$Not sure how to deal with the $$10π$$ and how we get $$\frac π 2$$.
 
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umzung said:
$$10π \left( \frac V {4π} \right)^{2/3} = 5\sqrt[3] {{V^2}\frac π 2}$$
It took me a little while to understand what you're trying to do. At first I thought you were trying to solve the equation above. Then I realized that the goal was to simplify the expression on the left side, above.

Also, be more careful on the letters you use for variables. In your relevant equation, you have v (lower case) on one side and V (upper case) on the other. That was confusing as well.
umzung said:
Not sure how to deal with the ##10π## and how we get ##\frac π 2##.
One thing to realize is that ##(a)^{\frac 2 3}## is equal to ##(a^2)^{\frac 1 3}##. Can you start simplifying based on this hint?
 
I think I have it now.
The key to the answer is that $$10\pi=((10\pi)^{3/2})^{2/3}$$
which I can then bring inside the brackets.
 

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