I'll give it a go...
The given Wave Equation is:
[itex]\frac{\partial }{\partial x_j}(C_{ijkl}\frac{\partial u_l}{\partial x_k}) - \frac{\partial^2 (\rho u_i)}{\partial t^2} = 0 .[/itex]
But we have the simplifications that density is constant in time and that the material is homogeneous. So we can pull out [itex]C_{ijkl}[/itex] and [itex]\rho[/itex] to give:
[itex]C_{ijkl}(\frac{\partial^2 u_l}{\partial x_j \partial x_k}) - \rho \frac{\partial^2 u_i} {\partial t^2} = 0 .[/itex]
We are then told that the material is isotropic. The lecture material gives an expression for the elastic tensor which is invariant under rotations, i.e. isotropic:
[itex]C_{ijkl} = \lambda \delta_{ij} \delta_{kl} + \mu (\delta_{ij} \delta_{kl} + \delta_{il} \delta_{jk})[/itex]
Thus, the new Wave Equation is given by:
[itex]\lambda \delta_{ij} \delta_{kl} (\frac{\partial^2 u_l}{\partial x_j \partial x_k}) + \mu (\delta_{ij} \delta_{kl}(\frac{\partial^2 u_l}{\partial x_j \partial x_k})+ \delta_{il} \delta_{jk}(\frac{\partial^2 u_l}{\partial x_j \partial x_k})) =\rho \frac{\partial^2 u_i} {\partial t^2}[/itex]
This simplifies to:
[itex]\lambda \frac{\partial^2 u_k}{\partial x_i \partial x_k} + \mu \frac{\partial^2 u_i}{\partial^2 x_j }+ \mu \frac{\partial^2 u_j}{\partial x_j \partial x_i} =\rho \frac{\partial^2 u_i} {\partial t^2}.[/itex]
This is not the same as the given solution:
[itex](\lambda + \mu) \frac{\partial^2 u_k}{\partial x_i \partial x_k} - \mu \frac{\partial^2 u_i}{\partial^2 x_i } =\rho \frac{\partial^2 u_i} {\partial t^2}.[/itex]