- #1

wuffle

- 26

- 0

## Homework Statement

This is a sub problem, the whole problem is find interval of convergence and radius of convergence but the thing I am having trouble with is how to simplify this

simplify the series

2*4*6*8*(2n)/2*4*6*8...(2n+2)

## Homework Equations

## The Attempt at a Solution

keys say 2*4*6*8...(2n)=2^n*n!

so 2^n*n!/2^(n+1)*(n+1)!=1/(2n+2)

my question is, HOW? how do u go from 2*4*6*8...(2n) to 2^n*n! or how do u get from

2*4*6*8*(2n)/2*4*6*8...(2n+2) to 1/(2n+2)

sorry for not using the proper tools, they are very confusing :(