Simplifying sin(3pi/2-x): An Exploration

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Homework Help Overview

The discussion revolves around the simplification of the trigonometric expression sin(3pi/2 - x). Participants are exploring the meaning of "simplify" in this context and the implications of different interpretations of the expression.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants are questioning the definition of "simplify" and whether it refers to rewriting the expression in a different form or finding a more basic representation. Some suggest using known trigonometric identities, while others express uncertainty about the intended meaning.

Discussion Status

The discussion is active, with participants providing hints and exploring different interpretations of the simplification process. There is a recognition of the ambiguity in the term "simplify" and a willingness to engage with various approaches without reaching a definitive conclusion.

Contextual Notes

There appears to be confusion regarding the expression's format, with participants clarifying the intended notation. The discussion also touches on the subjective nature of what constitutes a "simpler form."

rachael
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What does "simplify" means in this case:
Simplify each of the following:
1. sin(3pi/2-x)
 
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rachael said:
What does "simplify" means in this case:
Simplify each of the following:
1. sin(3pi/2-x)
Do you mean something like this:
\sin \left( \frac{3 \pi}{2 - x} \right)?
If you mean that, then I don't think it can be simplified any more. :wink:
 
nope i mean sin [(3pi/2)-x]
 
rachael said:
nope i mean sin [(3pi/2)-x]
Ahh, I see. I'll give you some hints. Do you know something like:
\sin (\pi + x) = - \sin x and
\sin \left( \frac{\pi}{2} - x \right) = \cos x?
 
In other words, "simplify" here means "write in a simpler form" which would be something like Asin(x)+ Bcos(x) rather than sin(\theta+x). In my opinion you would certainly be justified in arguing whether or not that is simpler but it is clearly what is intended.
 
In general:
sin(A \pm B)=sinA \, cosB \pm sinB \, cosA
cos(A \pm B)=cosA \, cosB \mp sinA \, sinB

-Dan
 
thank you...
 

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