Simplifying the derivative of y=3x²ln(x)

[anthonyk2013]

y=3x²Inx

u=3x²
v=Inx
du/dx=6x
dv/dx=I/x

y=u*v

dy/dx=(u)(dv/dx)+(v)(du/dx)

dy/dx=(3x²)(I/x)+(Inx)(6x)

Can I simplify this further

 

[Mark44]

y=3x²Inx

What is Inx? If you are going by what is on a button on a calculator, that is ln x (LN), for natural logarithm.

u=3x²
v=Inx
du/dx=6x
dv/dx=I/x

If v = ln(x), then dv/dx = 1/x, not I/x.

y=u*v

dy/dx=(u)(dv/dx)+(v)(du/dx)

dy/dx=(3x²)(I/x)+(Inx)(6x)

Can I simplify this further

Please post homework-type problems in the Homework & Coursework section, not in the technical math sections. I am moving this thread.

 

[anthonyk2013]

What is Inx? If you are going by what is on a button on a calculator, that is ln x (LN), for natural logarithm.
If v = ln(x), then dv/dx = 1/x, not I/x.


Please post homework-type problems in the Homework & Coursework section, not in the technical math sections. I am moving this thread.

It's not homework!

 

[Mark44]

But it's a homework-type problem, so this is where it goes.