RModule
- 2
- 0
Hello,
I'm a mathematics student specializing in (semi-)Riemannian geometry and relating this to relativity. My main reference is O'neill's "Semi-Riemanninan Geometry with Applications to Relativity".
This book defines the Robertson-Walker spacetime as follows:
Let S be a connected three-dimensional Riemanninan manifold of constant curvature k = -1,0,1. Let f>0 be a smooth function on an open interval I in R_1^1 Then the warped product M(k,f) = I \times_f S is called a RW spacetime. Explicitly M(k,f) is the manifold I\times S with line element -dt^2+ f^2(t)d\sigma^2 where d\sigma^2 is the line element of S.
Is this a non-standard definition? From what I can see on wiki, the manifold should be simply connected. Further, does this definition imply that M is orientable?
Because, from this definition \mathbb{R}P^3 \times I would be a RW spacetime, even though it is not simply connected. Which leads me to the following; S^3 and \mathbb{R}P^3 are locally "the same" but globally quite different. What relativistic implications would not being simply connected have on the spacetime? I guess you essentially could see the same stars from two(or more) different directions. Are there any other important differences?
Thank you.
I'm a mathematics student specializing in (semi-)Riemannian geometry and relating this to relativity. My main reference is O'neill's "Semi-Riemanninan Geometry with Applications to Relativity".
This book defines the Robertson-Walker spacetime as follows:
Let S be a connected three-dimensional Riemanninan manifold of constant curvature k = -1,0,1. Let f>0 be a smooth function on an open interval I in R_1^1 Then the warped product M(k,f) = I \times_f S is called a RW spacetime. Explicitly M(k,f) is the manifold I\times S with line element -dt^2+ f^2(t)d\sigma^2 where d\sigma^2 is the line element of S.
Is this a non-standard definition? From what I can see on wiki, the manifold should be simply connected. Further, does this definition imply that M is orientable?
Because, from this definition \mathbb{R}P^3 \times I would be a RW spacetime, even though it is not simply connected. Which leads me to the following; S^3 and \mathbb{R}P^3 are locally "the same" but globally quite different. What relativistic implications would not being simply connected have on the spacetime? I guess you essentially could see the same stars from two(or more) different directions. Are there any other important differences?
Thank you.
Last edited: