- #1
spj1
- 7
- 0
The problem:
sin(t) - cos(t) can be rewritten as ? - The answer is sqrt(2)cos(3PI/4 - t).
there is an equation Re^(xt)cos(bt - angle).
R = sqrt(A^2+B^2)
So i get the following answer:
sqrt(2)(cos(t - 3PI/4)).
Why does the correct answer have the 3PI/4 switched with the t??
sin(t) - cos(t) can be rewritten as ? - The answer is sqrt(2)cos(3PI/4 - t).
there is an equation Re^(xt)cos(bt - angle).
R = sqrt(A^2+B^2)
So i get the following answer:
sqrt(2)(cos(t - 3PI/4)).
Why does the correct answer have the 3PI/4 switched with the t??