Single slit Diffraction using green light

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SUMMARY

The discussion focuses on calculating the width of the central bright band in a single slit diffraction experiment using monochromatic green light with a wavelength of 546 nm and a slit width of 0.095 mm. The setup involves a screen positioned 75 cm from the slit. The correct width of the central bright band is determined to be 4.3 mm. A common misconception addressed is the measurement method, where participants mistakenly calculate the full distance to the first dark band instead of halving it to find the width of the bright band.

PREREQUISITES
  • Understanding of single slit diffraction principles
  • Familiarity with the equation D sin θ = m λ
  • Knowledge of wavelength measurement in nanometers
  • Basic trigonometry for angle calculations
NEXT STEPS
  • Research the derivation of the single slit diffraction formula
  • Learn about the impact of slit width on diffraction patterns
  • Explore experimental setups for measuring diffraction patterns
  • Study the effects of different wavelengths on diffraction results
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Students in physics, educators teaching wave optics, and anyone interested in experimental physics related to light behavior and diffraction patterns.

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Homework Statement




Monochromatic green light of wavelength
546 nm falls on a single slit with a width
of 0.095 mm. The slit is located 75 cm from
a screen. How wide will the central bright
band be?




Homework Equations



D sin 0dark = m 入

The Attempt at a Solution



Can someone tell me why i keep getting double of the answer? ans is 4.3 mm
 
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Aren't you measuring all the way to the centre of the dark band and considering that to be the width of the bright band? Surely you should stop halfway.


This is useful...

http://www.walter-fendt.de/ph14e/singleslit.htm"
 
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