Singular values of unitarily equivalent matrices

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SUMMARY

Two square matrices, A and B, are unitarily equivalent if A = QBQ* for some unitary matrix Q. The discussion establishes that A and B share the same singular values if and only if they are unitarily equivalent. The proof involves substituting A with QBQ* and using the properties of unitary matrices, specifically that Q* is the inverse of Q. This leads to the conclusion that the singular values of A and B must be identical.

PREREQUISITES
  • Understanding of unitary matrices and their properties
  • Knowledge of singular value decomposition (SVD)
  • Familiarity with matrix operations and definitions
  • Basic linear algebra concepts, particularly eigenvalues and eigenvectors
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  • Learn about singular value decomposition (SVD) and its applications
  • Explore the implications of matrix equivalence in linear algebra
  • Investigate the relationship between eigenvalues and singular values
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Homework Statement


If two square matrices, A and B are unitarily equivalent then A = QBQ* for some unitary Q of the same size as A and B. Prove that A and B are unitarily equivalent if and only if they have the same singular values


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The Attempt at a Solution


I started from the definition of singular values:

Au = sigma v for singular vectors u and v
A*v = sigma u
substitution A with QBQ*,
QBQ*u = sigma v
(QBQ*)*v = QB*Q*v = sigma u

Can't see how this leads to proving that the sigmas of A and B are the same..?
 
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If Q is unitary, the Q*=Q^(-1). Operate on the left by Q*.
 

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