Singularity/Invertibility of Matrix Product

  • Thread starter Thread starter Bipolarity
  • Start date Start date
  • Tags Tags
    Matrix Product
Click For Summary
SUMMARY

The discussion centers on proving that if the product of two square matrices A and B is invertible, then both matrices must also be invertible. The user attempted to prove the contrapositive, establishing that if either A or B is singular, then their product AB is also singular. They successfully demonstrated that if B is singular, then AB is singular, but faced challenges in proving the case for A. The conversation highlights the connection between singular matrices and non-trivial solutions to the homogeneous system Cx = 0.

PREREQUISITES
  • Understanding of matrix theory, specifically the properties of square matrices.
  • Knowledge of invertibility and singularity in matrices.
  • Familiarity with linear algebra concepts, including homogeneous systems.
  • Experience with contrapositive reasoning in mathematical proofs.
NEXT STEPS
  • Study the properties of singular matrices and their implications on matrix products.
  • Learn about the implications of the invertibility of matrices in linear transformations.
  • Explore the concept of homogeneous systems and their solutions in linear algebra.
  • Review proof techniques in linear algebra, particularly contrapositive proofs.
USEFUL FOR

Students and educators in linear algebra, mathematicians focusing on matrix theory, and anyone involved in mathematical proofs related to matrix properties.

Bipolarity
Messages
773
Reaction score
2

Homework Statement


Suppose that A and B are square matrices of the same order. Prove that if AB is invertible, then A and B are both invertible.


Homework Equations





The Attempt at a Solution


I attempted to prove the contrapositive, i.e. if at least one of A,B is singular, then AB is singular. I proved that if B is singular, then AB is singular, but I have not been able to prove that if A is singular, then AB is singular.

I know that this somehow involves the notion that singular matrices such as C have non-trivial solutions to the homogenous system Cx = 0. But I can't apply it correctly because I don't know the direction to follow.

Any hints?

BiP
 
Physics news on Phys.org
Bipolarity said:

Homework Statement


Suppose that A and B are square matrices of the same order. Prove that if AB is invertible, then A and B are both invertible.

Homework Equations


The Attempt at a Solution


I attempted to prove the contrapositive, i.e. if at least one of A,B is singular, then AB is singular. I proved that if B is singular, then AB is singular, but I have not been able to prove that if A is singular, then AB is singular.

I know that this somehow involves the notion that singular matrices such as C have non-trivial solutions to the homogenous system Cx = 0. But I can't apply it correctly because I don't know the direction to follow.

Any hints?

BiP

If A is singular then Av=0 for some nonzero vector v. Since you've already shown B is nonsingular then v=Bu for some nonzero vector u, yes?
 

Similar threads

  • · Replies 69 ·
3
Replies
69
Views
10K
Replies
42
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
24
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
53K
  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 7 ·
Replies
7
Views
7K
  • · Replies 15 ·
Replies
15
Views
5K