Siren Wavelength for Car Travelling North at 29.4 m/s

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The ambulance traveling North at 64.1 m/s emits a siren frequency of 705 cycles/s, while a car traveling North at 29.4 m/s hears this sound. The wavelength of the siren at the car driver's position is calculated to be 0.486 meters using the formula wavelength = velocity / frequency, with the speed of sound at 343 m/s. As the ambulance approaches, the wavelength decreases due to the Doppler effect, resulting in a higher frequency and pitch perceived by the car driver. Understanding this effect is crucial for drivers to ensure safety on the road.
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An ambulance is traveling North at 64.1 m/s, approaching a car that is also traveling North at 29.4 m/s. The ambulance driver hears his siren at a frequency of 705 cycles/s. The velocity of sound is 343 m/s. What is the wavelength at the car driver's position for the sound from the ambulance's siren? Answer in units of m.
 
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Do you know those 4 cases (actually only one useful in this problem) of Doppler effect...?Which case of the 4 does this problem correspond to?

You should always review the theory first?

Daniel.
 


The wavelength at the car driver's position for the sound from the ambulance's siren can be calculated using the formula: wavelength = velocity / frequency. In this case, the velocity of sound is given as 343 m/s and the frequency is 705 cycles/s. Therefore, the wavelength can be calculated as:

wavelength = 343 m/s / 705 cycles/s = 0.486 m

This means that the sound waves from the ambulance's siren have a wavelength of 0.486 meters at the car driver's position. This is important to note because as the ambulance approaches the car, the wavelength of the sound waves will decrease due to the Doppler effect. This will result in a higher frequency and a higher pitch of the siren as perceived by the car driver. It is important for drivers to be aware of this effect and adjust their driving accordingly to avoid potential accidents.
 
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