Situation involving gravity, a quarter-circular incline plane, and friction.

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SUMMARY

The discussion revolves around a physics problem involving a block of mass 4.0 kg sliding down a quarter-circular incline and then along a rough horizontal surface. The block experiences a frictional force of 5 N, resulting in an acceleration of 1.25 m/s² while sliding on the horizontal surface. It comes to rest after sliding a distance of 3 meters, taking approximately 1.55 seconds to do so. The radius of the quarter-circular incline can be determined using conservation of energy principles.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of kinematic equations (e.g., x = 1/2 at² + v₀t + x₀)
  • Familiarity with the concept of friction and its effects on motion
  • Basic principles of conservation of energy in physics
NEXT STEPS
  • Learn how to apply conservation of energy to determine the height of an incline
  • Study kinematic equations for uniformly accelerated motion
  • Explore the effects of friction on motion and how to calculate frictional forces
  • Investigate the relationship between mass, force, and acceleration in various contexts
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the dynamics of motion on inclined planes and the effects of friction.

Woolverton
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1. A block of mass 4.0 kg is released from rest at the top of a frictionless incline shaped as a quarter-circle of radius r. At the bottom of the incline, the block slides along a rough horizontal surface, experiencing frictional force of 5 N. The block comes to rest after sliding a distance of 3 meters.

(a) What is the magnitude of the block's acceleration while it slides along the rough horizontal surface?

(b) For how much time does the block slide along the rough surface before coming to rest?

(c) What is the radius of the quarter-circular incline plane?


I've drawn a sketch of the situation for your convenience. I hope it helps.

sketch_zps4d0f1c2b.jpg


2.
g= 10 m/s2
F= m/a
x= 1/2 * at2 + v0t + x0


3.
(a)

m = 4 kg
F = 5 N

F = ma
a= F/m

a = 5/4 = 1.25 ms/2 (I'm sure this is correct)

(b)

d = 3 m
a = 1.25 m/s2

a= = d/t2
t= (d/a)1/2

t= (3/1.25)1/2 (not very confident about this one)

(c)

I don't know what equation to use, but I'm sure it involves the velocity of the object as it comes off of the incline.
 
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Welcome to PF!

HI Woolverton! Welcome to PF! :smile:
Woolverton said:
(a)

m = 4 kg
F = 5 N

F = ma
a= F/m

a = 5/4 = 1.25 ms/2 (I'm sure this is correct)

erm :redface: … yes, but shouldn't it be negative? :wink:
(b)

d = 3 m
a = 1.25 m/s2

a= = d/t2
t= (d/a)1/2

t= (3/1.25)1/2 (not very confident about this one)

try your x = at + 1/2 a t2 equation again …

you seem to have lost a 2 somewhere :redface:
(c)

I don't know what equation to use, but I'm sure it involves the velocity of the object as it comes off of the incline.

use conservation of energy (to find the height) :smile:
 

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