Sketching/solving polar: r^2=a^2*cos2t

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Homework Help Overview

The discussion revolves around sketching the polar equation r² = a² cos(2θ) and converting it into Cartesian coordinates. Participants are exploring the relationship between polar and Cartesian systems in the context of graphing this specific equation.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to convert the polar equation to Cartesian coordinates but are encountering difficulties. Some suggest directly sketching the polar relation without conversion. Others propose evaluating specific angles to determine corresponding r values for plotting.

Discussion Status

There is a mix of approaches being discussed, with some participants advocating for direct polar plotting while others are focused on conversion to Cartesian coordinates. Hints and suggestions have been provided to evaluate specific angles and their corresponding distances from the origin.

Contextual Notes

Participants express uncertainty about the necessity of converting to Cartesian coordinates and question how to effectively sketch in polar coordinates. The parameter 'a' is mentioned as a variable that influences the graph, but its specific value remains undefined in the discussion.

ponjavic
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Sketch (in the x-y plane): r^2=a^2*cos2t where r and t are polar coordinates.

I simply am not able to convert this formula to x and y.
I have gotten as far as:
(x^2+y^2)^2=a^2(x^2-y^2)
or r^4=a^2(r^2*cost^2-r^2*sint^2)
using r = x^2+y^2, cos2t=1-sint^2, x = rcost and y = rsint but I simply can not get any further.

Please give any hints you think might help me solve this.
 
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I don't see why you need to convert to Cartesian coordinates. You can make a sketch of the relation directly. [itex]\theta[/itex] is the angle relative to the x-axis and r is the distance from the origin.
 
Try this: take [itex]\theta= 0, \pi/4, \pi/2, \pi/3,[/itex] etc. and see what you get for r: graph those points in polar coordinates.
 
Last edited by a moderator:
well, there is now way to isolate y from x using cartesian coordianres, its really easier to see what's going on in polar coordinates.
the best way is to do as suggested, and plot what you get on x-y plane.
 
Tide said:
I don't see why you need to convert to Cartesian coordinates. You can make a sketch of the relation directly. [itex]\theta[/itex] is the angle relative to the x-axis and r is the distance from the origin.
I don't know how to use polar coordinates to sketch, If I have it in cartesians I could do y=0, y'=0, x=0, find asymptotes and such.
How can I find this to help me sketch in polar coordinates?

[itex]\theta= 0, \pi/4, \pi/2, \pi/3,[/itex]
I'll try to work around with this and see what it gets me, what's a^2 though?
 
Last edited:
pon,

Do as Halls suggested. For example, when [itex]\theta = 0[/itex] you know that the point lies on the x axis. Evaluate the expresstion when [itex]\theta = 0[/itex] to find out how far from the origin the corresponding point is. Then place a point r units from the origin and on the x-axis corresponding to that point.

Next try [itex]\theta = \pi / 4[/itex] which you know lies along a line at 45 degrees above the x axis. Find the distance to that point using your formula and place a point that far from the origin and along the line y = x on your graph. Do this for several values of [itex]\theta[/itex].

Also, your graph will depend on the parameter a. Do all of the above for different values of a like a = 1, a = 1/2, a = 2 etc.
 

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