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## Homework Statement

the velocity of a skydiver falling to the ground is governed by:

m dv/dt = mg - kv^2

solve for v(t) with initial conditions v(0) = 0

i rearranged equation into standard form:

v' + (k/m)v^2 = g

so i got an integrating factor, mu(x) = e^integ(k/m), but does the fact that the v is squared prohibit me from using an integrating factor?

thanks