(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A metal bar with length L, mass m, and resistance R is placed on frictionless metal rails that are inclined at an angle [itex]\phi[/itex] above the horizontal. The rails have negligible resistance. A uniform magnetic field of magnitude is directed downward in the figure B. The bar is released from rest and slides down the rails.

(In the diagram it can be seen that the bar divides a rectangle into two smaller rectangles. As the bar slides, one grows, and the other shrinks.)

What is the terminal speed of the bar?

2. Relevant equations

[itex]\cal{E}=IR[/itex]

[itex]\cal{E}=-\frac{d\Phi_m}{dt}[/itex]

3. The attempt at a solution

Effective gravity has magnitude

[itex]mg\sin\phi[/itex]

The two wire loops formed by the bar have respective emfs

[itex]{\cal E}_{1}=-\frac{d\Phi_{1}}{dt}=-BLv[/itex]

[itex]{\cal E}_{2}=-\frac{d\Phi_{2}}{dt}=BLv[/itex]

Therefore, the current along the bar is

[itex]I=\frac{-{\cal E}_{1}+{\cal E}_{2}}{R}=\frac{2BLv}{R}[/itex]

The negative sign appears because one loop runs clockwise and the other counterclockwise.

This creates a force

[itex]F=ILB=\frac{2B^{2}L^{2}}{R}v[/itex]

and an effective force

[itex]\frac{2B^{2}L^{2}}{R}v\cos\phi[/itex]

The two are in equilibrium when

[itex]\frac{2B^{2}L^{2}}{R}v = mg\tan\phi[/itex]

[itex]v = \frac{Rmg\tan\phi}{2B^{2}L^{2}}[/itex]

The online homework system says this is incorrect, and I can't fiqure out why.

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# Homework Help: Sliding Bar in a Uniform Magnetic Field

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