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Small=high mass at quantum level, but big=high mass at classical level. Why?

  1. Feb 20, 2012 #1
    At a classical physics level, physically big equates to big mass, but at the sub-atomic level, small seems to equate to big mass i.e. (short wavelength big mass relationship. "momentum=h/wavelength"). Any ideas why there is this complete contrast?
     
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  3. Feb 21, 2012 #2
    Last edited: Feb 21, 2012
  4. Feb 21, 2012 #3

    Vanadium 50

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    No they don't.

    If you don't know the answer, it's not necessary to reply.
     
  5. Feb 21, 2012 #4
    In classical physics you have an intuition that all objects have constant density. So bigger size with the same density yields bigger mass.

    In quantum physics "density" is not constant. You rather have some constant amount of something (aether, waves) and you squeeze it. The classical intuition would be that the mass of a squeezed body remains constant, but from special relativity you get that the energy of the body gets higher. And higher energy means higher mass.

    Those two approaches can be considered at the same time. You get then the balance between classical and quantum physics. This yields the definition of Planck mass and the Bekenstein bound.
     
  6. Feb 21, 2012 #5

    Demystifier

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    It is not so much classical vs quantum, but rather one vs many particles. For one quantum particle, smaller length x means more energy e, as you said. But if you have MANY (say N) such small particles at DIFFERENT positions, then total energy and total length scale like
    E=Ne
    X=Nx
    so bigger N means both bigger E and bigger X.
     
  7. Feb 21, 2012 #6
    But if you use DeBroglie's wave/particle formula on a large object, say a rock, you get momentum=h/wavelength, so a big rock, at the same speed as a little rock, has bigger momentum yet smaller wavelength - yet it's made up from more than one particle.
     
  8. Feb 21, 2012 #7
    Becuase on a quantum-level, the universe isn't intuitive?
     
  9. Feb 21, 2012 #8

    Demystifier

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    Yes, but it is incorrect to apply the DeBroglie's wave/particle formula on an object consisting of many particles. For example, the nucleus of an atom is very small (much smaller than the atom itself), and yet a heavier nucleus is bigger than a lighter one. That's because the nucleus consists of many particles.

    More precisely, it is not enough to have many particles. In addition, these particles must be FERMIONS (which protons and neutrons in the nucleus are), so that you cannot put all them at the same place.

    If you have BOSONS (e.g., photons), then you can put many of them in the same state, so with a fixed wavelength (fixed energy of one particle) the size of N bosons may not depend on the total energy of N particles.
     
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