So i did this question and got an answer of 43 N i was wondering if

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SUMMARY

The discussion centers on calculating the minimum force required to keep a 22 kg box at rest on a 45-degree inclined ramp with static and kinetic friction coefficients of 0.78 and 0.65, respectively. The participant arrived at a force of 43 N and sought validation from others. The problem involves breaking down forces into their x and y components and applying the equation Fnet = 0, along with the frictional force equation Ff = UFn, to ensure the box remains stationary.

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So i did this question and got an answer of 43 N i was wondering if someone else could try it and tell me what they get.. it its not the same ill explain my steps and see where i went wrong.

Homework Statement


A box with a mass of 22 kg is at rest on a ramp inclined at 45 to the horizontal. The coefficients of friction between the box and the ramp are Us = 0.78 and Uk = 0.65.
Determine the magnitude of the smallest force that can be applied onto the top of the box, perpendicular to the ramp, if the box is to remain at rest.


Homework Equations


Fnet = 0
Ff = UFn

The Attempt at a Solution


I broke the question down into its x and y components.
 
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Yes, that's what I get as well.
 
okay good! thank you!
 

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