Solenoid power and conical area

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SUMMARY

This discussion focuses on calculating heat generation in tubular solenoid actuators, specifically pull-type designs. The heat generation is determined using the formula I²R, where R is calculated based on wire length and resistance per unit length from American Wire Gauge specifications. The user seeks to understand the implications of using a conical surface area for the plunger, particularly for achieving a force output of 2500N with a 1mm stroke, and inquires about the apex angle of the armature. Additionally, the discussion touches on the need to calculate heating due to eddy currents in core materials.

PREREQUISITES
  • Understanding of solenoid actuator design principles
  • Familiarity with electrical resistance calculations
  • Knowledge of American Wire Gauge (AWG) standards
  • Basic concepts of eddy currents in conductive materials
NEXT STEPS
  • Research methods for calculating eddy current losses in magnetic materials
  • Explore advanced solenoid design techniques for optimizing force output
  • Learn about thermal management strategies in solenoid actuators
  • Investigate the effects of different armature geometries on solenoid performance
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Engineers and designers working on solenoid actuator systems, electrical engineers focusing on thermal management, and anyone involved in optimizing actuator performance for specific applications.

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Hello ,

I have been wanting to find out the how heat generation of a tubular solenoid (pull-type)actuator is calculated?

Secondly, why do most solenoid design use a plunger with a flat face/conical surface area . If I am looking for 1mm of stroke.. and a force output of 2500N, what apex angle of armature could I use. IF so, what would be the heat generation.

Regards
 
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Resistive heating of the windings? Eddy currents in the core material?
 
Heys,

Resistive heating due to wirings, heat generation = I^2*R.

R is found by length * (ohm/m), which is taken from American Wire Gauge
Length is found by N,no. of wire turns multiply by the average circumference of wire coil around the bobbin.

I, current is found by fixing F=2500N, air permeability, surface area of the cone, air gap is 1mm, then vary N to find I. After which able to find heat generation from resistance of wire.

Please correct me if I am wrong..!

By the way, how do I find heating due to eddy current in core materials.

Regards
 

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