Solid mechanics, castiglianos second theorem

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SUMMARY

This discussion focuses on applying Castigliano's Second Theorem to determine beam deflection under an applied force P due to flexural deformation. The formula used is delta = dU / dP, where U represents the strain energy. Participants discuss calculating the moment (M) and shear force (V) to derive the strain energy U using the formula U = integral(0 to L) (M^2/2*E*L) dl. Additionally, the conversation touches on determining support reactions for a structure while considering negligible axial deformations.

PREREQUISITES
  • Understanding of Castigliano's Theorem
  • Knowledge of beam deflection analysis
  • Familiarity with strain energy concepts
  • Proficiency in calculating moments and shear forces
NEXT STEPS
  • Study the derivation of strain energy in beams using Castigliano's Theorem
  • Learn about calculating support reactions in statically determinate structures
  • Explore advanced applications of Castigliano's Theorem in complex loading scenarios
  • Investigate numerical methods for beam deflection analysis
USEFUL FOR

Structural engineers, mechanical engineers, and students studying solid mechanics who are looking to deepen their understanding of beam deflection and strain energy calculations using Castigliano's Theorem.

kantti
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So... I need to determine the deflection of the beam under applied force P due to flexural deformation using castiglianos second theorem.

Simply, delta = dU / dP

How do I determine the strain energy U for the given system?
 
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first calculate M and V ...from there calculate U using formulae...
as in one using moment is...
U=integral(0 to L) (M^2/2*E*L) dl...
similarly go wid V..
den differentiate...to get final displacement...
 
Thank you for the reply.

Now I'm stuck on a different problem. I want to determine the support reactions for given structure using the same theorem (see attachment). Axial deformations are considered negligible. This is what i got so far, but now I'm a bit clueless on how to continue. Be gentle, I'm lacking some necessary literature =)
 

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well i can solve it...
but there is some kind of policy that for new problm u have to make a new thread...
:smile:
 

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