Solid mechanics-how do i find the maximum momentum in this question?

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The discussion focuses on determining the maximum momentum (Mo) in solid mechanics using the xx stress function. The user derived the equation Mo=(σ*h^3*b)/(12c) and explored the implications of varying the constant C. The conclusion reached is that as C approaches zero, Mo tends toward infinity, indicating that the maximum value occurs at this limit. The user ultimately resolved their confusion regarding the integral calculations and confirmed that C=0 yields the maximum momentum.

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Solid mechanics-how do i find the maximum momentum in this question?
in this question, i am given the function for the xx stress as seen in the diagram below:
http://lh6.ggpht.com/_H4Iz7SmBrbk/SvG3wUaPVAI/AAAAAAAAB6w/sMKXVGWomi8/Capture1.JPG

i am asked to sketch the stress distribution, which i have done
http://lh3.ggpht.com/_H4Iz7SmBrbk/SvG3wPYlmdI/AAAAAAAAB6s/rd9T_ED6MK0/Capture.JPG

now i am asked to find the value of C which will give me the maximum value for Mo, which as far as i can see is Moment about the z axis.

what I've done is

Mz= -ʃʃ {(σxx)*y} dA

now i know that there are 3 options,(3 functions for σxx) but i know that for y>=c and y<c the function for σxx is constant and -ʃʃ {y} dA is 0,(1st moment of area)

therefore i think i must find it where -c<y<c,

-ʃʃ {(-σy/c)*y} dA= σ/c * ʃʃ {(y^2} dA
=σ/c * ʃʃ {(y^2} dydz [(z from -b/2 to b/2), (y from -h/2 to h/2)]
and i get

Mo=(σ*h^3*b)/(12c)

now how do i find thevalue for c that will give me the maximum Mo?? if c=0 Mo is infinite ??

i thought maybe to find the derivative and compare to 0 but by what? y? z? either way i don't see how that would help, since i am looking for the maximum "c" value, then i thought maybe dMo/dC but i don't think so.
 
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never mind, my integral was totally wrong, got it right though, c=0, thanks anyway
 

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