1. The problem statement, all variables and given/known data determine by inspection at least two solutions of the given first-order IVP dy/dx = 3y2/3 y(0)=0 2. Equations: integral xa dx= xa+1/(a+1)+constant 3. The attempt at a solution change its form to 1/y2/3 dy/dx =3 integrate both sides with respect to x then it will be 1/y2/3 dy = 3dx now integrate to get y1/3/(1/3)=3x+c for y(0)=0 then c=0 then y1/3/(1/3) =3x then y=x3 Is that right? does I miss any condition or jumped over some steps?