Solution molarity change in electrolytic cell

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SUMMARY

The discussion centers on calculating the change in molarity of copper ions in a 1L aqueous 1M copper(II) sulfate solution during electrolysis when 0.4 moles of electrons pass through the cell. The correct answer is determined to be C) 1.0 M, as 0.2 moles of Cu2+ are deposited at the anode and 0.2 moles are absorbed at the cathode, resulting in no net change in concentration. The reasoning provided confirms that the molarity remains unchanged despite the electron transfer.

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  • Understanding of electrolysis and its principles
  • Knowledge of molarity and concentration calculations
  • Familiarity with copper(II) sulfate solution properties
  • Basic concepts of oxidation and reduction reactions
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  • Learn about the Faraday's laws of electrolysis
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TT0
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Homework Statement



The diagram below shows an electrolysis cell which contains 1L of an aqueous 1M copper(II)sulfate solution.

upload_2016-6-30_15-43-12.png


If 0.4 moles of electrons pass through the cell, the concentration of copper ions after passage of the charge will be

A) 0.4 M

B) 0.8 M

C) 1.0 M

D) 1.2M.

2. Homework Equations

The Attempt at a Solution



I chose C because if 0.4 moles of electrons pass through the cell, then that means 0.2 moles of Cu2+ will be deposited into the solution from the anode and that means 0.2 moles of Cu2+ will be absorbed by the cathode. This gives no net change in molarity in the solution. Is this correct?

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