Solution Of A Differential Equation]

In summary, the conversation discusses a second order differential equation, d^2(y)/dx^2 = c/x, where c is an arbitrary constant. The solution is hinted to take the form of a trigonometric equation, but the correct solution is actually dv/dx = c/x, where v is the derivative of y. Some additional work is needed to find the final solution.
  • #1
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Hi all I was wondering if i could get some help with this.

1. I need to be able to solve a second order differential equation,

2. d^2(y)/dx^2= c/x

where c is an arbitary constant.

I was thinking that the solution would take form of a trigonometrial eqauation, would this be correct?

Thanks for your time

N



The Attempt at a Solution

 
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  • #2
NEWO said:

The Attempt at a Solution

You left this part of the template blank. What work have you done on the problem?
 
  • #3
Well it's quite easy, here's a hint: succesive 'something' will do the trick.
 
  • #4
WHY would you tnink "that the solution would take form of a trigonometrial eqauation"?
 
  • #5
NEWO said:
I was thinking that the solution would take form of a trigonometrial eqauation, would this be correct?

Hi NEWO! :smile:

Noo … you're thinking of d²y/dx² = -cy.

Hint: just say the equation in ordinary English:

"y is a function of x, and if you differentiate it twice, you get c/x." :smile:
 
  • #6
If you let [itex]v= dy/dx[/itex] then [itex]d^2y/dx^2= dv/dx[/itex] so your equation becomes [itex]dv/dx= c/x[/itex]. What is v(x)?
 
  • #7
Halls, isn't your hint really the solution?
 
  • #8
Well, almost. There is still a tiny amount of work to be done. And I suspect that "NEWO" won't bother to come back to look at the responses.
 

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