Solution Of A Differential Equation]

• NEWO
In summary, the conversation discusses a second order differential equation, d^2(y)/dx^2 = c/x, where c is an arbitrary constant. The solution is hinted to take the form of a trigonometric equation, but the correct solution is actually dv/dx = c/x, where v is the derivative of y. Some additional work is needed to find the final solution.

NEWO

Hi all I was wondering if i could get some help with this.

1. I need to be able to solve a second order differential equation,

2. d^2(y)/dx^2= c/x

where c is an arbitary constant.

I was thinking that the solution would take form of a trigonometrial eqauation, would this be correct?

N

NEWO said:

The Attempt at a Solution

You left this part of the template blank. What work have you done on the problem?

Well it's quite easy, here's a hint: succesive 'something' will do the trick.

WHY would you tnink "that the solution would take form of a trigonometrial eqauation"?

NEWO said:
I was thinking that the solution would take form of a trigonometrial eqauation, would this be correct?

Hi NEWO!

Noo … you're thinking of d²y/dx² = -cy.

Hint: just say the equation in ordinary English:

"y is a function of x, and if you differentiate it twice, you get c/x."

If you let $v= dy/dx$ then $d^2y/dx^2= dv/dx$ so your equation becomes $dv/dx= c/x$. What is v(x)?

Halls, isn't your hint really the solution?

Well, almost. There is still a tiny amount of work to be done. And I suspect that "NEWO" won't bother to come back to look at the responses.