Solution Of A Differential Equation]

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Homework Help Overview

The discussion revolves around solving a second order differential equation of the form d²y/dx² = c/x, where c is an arbitrary constant. Participants are exploring the nature of the solution and its potential forms.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster considers whether the solution might be a trigonometric equation and questions the correctness of this assumption. Other participants provide hints and suggest alternative approaches, including letting v = dy/dx to reformulate the equation.

Discussion Status

Participants are actively engaging with the problem, offering hints and questioning assumptions. There is a mix of suggestions and clarifications, but no explicit consensus has emerged regarding the solution approach.

Contextual Notes

Some participants express concern that the original poster may not return to the discussion, which could affect the continuity of the dialogue. Additionally, there is an indication that the original poster's understanding of the problem may need further clarification.

NEWO
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Hi all I was wondering if i could get some help with this.

1. I need to be able to solve a second order differential equation,

2. d^2(y)/dx^2= c/x

where c is an arbitary constant.

I was thinking that the solution would take form of a trigonometrial eqauation, would this be correct?

Thanks for your time

N



The Attempt at a Solution

 
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NEWO said:

The Attempt at a Solution

You left this part of the template blank. What work have you done on the problem?
 
Well it's quite easy, here's a hint: succesive 'something' will do the trick.
 
WHY would you tnink "that the solution would take form of a trigonometrial eqauation"?
 
NEWO said:
I was thinking that the solution would take form of a trigonometrial eqauation, would this be correct?

Hi NEWO! :smile:

Noo … you're thinking of d²y/dx² = -cy.

Hint: just say the equation in ordinary English:

"y is a function of x, and if you differentiate it twice, you get c/x." :smile:
 
If you let [itex]v= dy/dx[/itex] then [itex]d^2y/dx^2= dv/dx[/itex] so your equation becomes [itex]dv/dx= c/x[/itex]. What is v(x)?
 
Halls, isn't your hint really the solution?
 
Well, almost. There is still a tiny amount of work to be done. And I suspect that "NEWO" won't bother to come back to look at the responses.
 

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