Solution to Schrodinger's Equation Homework Statement

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SUMMARY

The discussion focuses on demonstrating that the wave function \(\Psi(x,t) = A \sin(kx - \omega t)\) does not satisfy the time-independent Schrödinger Equation (TISE). The participant differentiates the wave function with respect to time and space, yielding \(\partial \Psi(x,t)/\partial t = -\omega A \cos(kx - \omega t)\) and \(\partial^2 \Psi(x,t)/\partial x^2 = -k^2 A \sin(kx - \omega t)\). The conclusion is that the original function fails to meet the criteria set by the TISE, which is expressed as \(H\psi = E\psi\), where \(E\) represents the eigenvalue.

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Homework Statement


Show that the function [tex]\Psi(x,t)=Asin(kx- \omega t)[/tex] does not satisfy the time-independent Schrödinger Equation.

Homework Equations


Time independet SE

The Attempt at a Solution


I think i have to solve for derivative of [tex]\Psi(x,t)/t[/tex] and second derivative of [tex]\Psi(x,t)/x[/tex] but I'm not sure how to answer the question.

I attempted to differentiate the wave function with respect to time and space so that i got
[tex]\partial\Psi(x,t)/\partial t = -\omega Acos(kx-\omegat)[/tex]
and that [tex]\partial^2\Psi(x,t)/\partial x^x = -kAsin(kx-\omegat)[/tex]

If so, how do i prove that the original function does not satisfy the TDSE?
 
Last edited:
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The time-independent Schrödinger equation says Hψ = Eψ, where E is the eigenvalue. The Hamiltonian will tell you what to differentiate with respect to.
 

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